2y^3+12y^2=80y

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Solution for 2y^3+12y^2=80y equation:


Simplifying
2y3 + 12y2 = 80y

Reorder the terms:
12y2 + 2y3 = 80y

Solving
12y2 + 2y3 = 80y

Solving for variable 'y'.

Reorder the terms:
-80y + 12y2 + 2y3 = 80y + -80y

Combine like terms: 80y + -80y = 0
-80y + 12y2 + 2y3 = 0

Factor out the Greatest Common Factor (GCF), '2y'.
2y(-40 + 6y + y2) = 0

Factor a trinomial.
2y((-10 + -1y)(4 + -1y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'y' equal to zero and attempt to solve: Simplifying y = 0 Solving y = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y = 0

Subproblem 2

Set the factor '(-10 + -1y)' equal to zero and attempt to solve: Simplifying -10 + -1y = 0 Solving -10 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1y = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1y = 0 + 10 -1y = 0 + 10 Combine like terms: 0 + 10 = 10 -1y = 10 Divide each side by '-1'. y = -10 Simplifying y = -10

Subproblem 3

Set the factor '(4 + -1y)' equal to zero and attempt to solve: Simplifying 4 + -1y = 0 Solving 4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1y = 0 + -4 -1y = 0 + -4 Combine like terms: 0 + -4 = -4 -1y = -4 Divide each side by '-1'. y = 4 Simplifying y = 4

Solution

y = {0, -10, 4}

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